On 15-Oct-2009 flw wrote: > Even if there is no defined $@, it also need to alarm(0).
Maybe I'm being dense, but I don't see how the eval {} could exit with an alarm
still set but $@ not set. Or is there some magic to alarm() and SIG{ALRM} that
I'm unaware of.
Also, could you write a test case for this?
-Philip
