I think I have run into a bug when using a Hyperlink formula. My code is simply trying to insert a hyperlink into a cell, calling the setCellFormula on a cell I have created:
cell.setCellFormula( "HYPERLINK( \"http://jakarta.apache.org\";, \"Jakarta\" )" ); This always gets a Runtime Exception in the FormulaParser. However, if you call cell.setCellFormula( "HYPERLINK( \"jakarta\", \"Jakarta\" )" ); then it works (but does not give the desired results). It appears to me that the FormulaParser treats BOTH the : and . characters as meaningful and won't allow an http:// string to be passed through. Any ideas? --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
