Hi,

Numbered lists are not supported yet.

I think we know how PowerPoint stores this information, we just need time to
implement it :). Actually numbers and bullets are the same, the difference is 
only how
they are decorated.

Regards, Yegor

TP> Hi List,

TP> I'm experiencing a problem when I try to differ numbered lists from 
TP> bulleted lists.

TP> The paragraph flags should indicate the difference, shouldn't it?

TP> thanks in advance,

TP> Tales Paiva

TP> Erez Eisenstein wrote:
>> Thanks, I'll try that   :)
>> 
>> 
>> 
>> -----Original Message-----
>> From: Yegor Kozlov [mailto:[EMAIL PROTECTED] 
>> Sent: Monday, October 09, 2006 6:20 PM
>> To: POI Users List
>> Subject: Re: Numbering formats of lines of text in PPT files
>> 
>> Hi,
>> 
>> Recently we added RuchTextRun.getIndentLevel() which returns the
>> indentation level of a line.
>> 
>> In your example it should return 0 for "first line", "second line",
>> "third line"
>> and 1 for sub-lines:
>> 
>> 1. first line  //indent=0
>>         a.      first sub-line      //indent=1
>>         b.      second sub-line     //indent=1
>> 2.      second line //indent=0
>> 3.      third line  //indent=0
>> 
>> 
>> Regards, Yegor
>> 
>> EE> Hi Nick, I'm having the following problem:
>> 
>> EE> After extracting several lines of text from a TextBox, if the lines
>> were
>> EE> numbered, with also sub-numbered, I can't tell which line is which.
>> 
>> EE> Example:
>> 
>> EE> 1. first line
>> EE>         a.      first sub-line
>> EE>         b.      second sub-line
>> EE> 2.      second line
>> EE> 3.      third line
>> 
>> EE> will come out looking like this:
>> 
>> EE> *       first line
>> EE> *       first sub-line
>> EE> *       second sub-line
>> EE> *       second line
>> EE> *       third line
>> 
>> EE> All of these lines appear in the same TextRun instance, I got by
>> EE> invoking the getTextRun() method of TextBox class. I can't tell from
>> EE> each line's attribute (color, font, size, etc.) which line is a
>> sub-line
>> EE> of which.
>> 
>> EE> Is there a solution to this I'm over looking?
>> 
>> EE> Thanks
>> 
>> EE>
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>> 
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>> 
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