Is there a reason why no tclsh symlink is made by the tcl ports?
I'm trying to make a port that uses tcl scripts, and I'm not
sure how to give it a path to the interpreter. I guess I could
require tcl8.4 and use that full path, but it seems messy, and
would require them, later down the road, to keep multiple tcl
versions around when it's not necessary.
Maybe like this?
Index: Makefile
===================================================================
RCS file: /cvs/ports/lang/tcl/8.4/Makefile,v
retrieving revision 1.14
diff -u -p -r1.14 Makefile
--- Makefile 8 Jan 2006 13:08:01 -0000 1.14
+++ Makefile 26 Sep 2006 01:51:44 -0000
@@ -6,7 +6,7 @@ COMMENT= "Tool Command Language"
VERSION= 8.4.7
DISTNAME= tcl${VERSION}-src
-PKGNAME= tcl-${VERSION}p1
+PKGNAME= tcl-${VERSION}p2
SHARED_LIBS= tcl84 1.0
CATEGORIES= lang lang/tcl
MASTER_SITES= ${MASTER_SITE_SOURCEFORGE:=tcl/}
@@ -50,5 +50,6 @@ post-install:
${INSTALL_SCRIPT_DIR} ${PREFIX}/share/aclocal
cp ${WRKSRC}/tcl.m4 ${PREFIX}/share/aclocal
ranlib ${PREFIX}/lib/libtcl84.a
+ ln -sf tclsh8.4 ${PREFIX}/bin/tclsh
.include <bsd.port.mk>
Index: pkg/PLIST
===================================================================
RCS file: /cvs/ports/lang/tcl/8.4/pkg/PLIST,v
retrieving revision 1.6
diff -u -p -r1.6 PLIST
--- pkg/PLIST 18 Sep 2004 12:52:55 -0000 1.6
+++ pkg/PLIST 26 Sep 2006 01:51:45 -0000
@@ -1,6 +1,7 @@
@comment $OpenBSD: PLIST,v 1.6 2004/09/18 12:52:55 espie Exp $
@option no-default-conflict
@conflict tcl->=8.4,<8.5
+bin/tclsh
bin/tclsh8.4
include/tcl8.4/
include/tcl8.4/generic/
