Hallo If you are just working with distances of 1/4 of a mile I guess it would be easier to work in meters. If you have a srid with the unit meters you could do something like this I guess select st_Z(a.the_geom)-st_Z(b.the_geom) from (select user_input_point) a, (select the_geom from the_point_dataset) b where st_dwithin(a.the_geom,b.the_geom,400(or the exact number in meters of 1/4 of a mile)) I don't know if st_dwithin consider the third dimension or just calculate from 2d Hope this helps Nicklas
2009-03-10 MWilson Matthew wrote: > Good evening, Im a total postGIS newbie and Ive done some searching but I havent found an answer yet. Ive found and tried using the st_distance_spheroid function, and that seems to return a result as I would expect. However, I have a project where my goal is to determine what points fall within ΒΌ mile of a point that a user would specify as well as determining the elevation difference to the selected points from the user specified point. Ive defined my geometry field with the Z value that weve pre-calculated, and that seems to show up properly when looking at the values using the st_AsEWKT function. I was initially thinking I would have to generate a line object for the two points in question using ST_Makeline, use that distance with the st_length3d_spheroid function to compare with the 2d distance returned by st_distance_spheroid and calculate for the other side of the triangle to get the elevation difference, but that doesnt seem to match the elevation numbers I have. I did have to transform everything into latlong to get the distance functions to workbut I have a feeling that Im over thinking this. There should be some kind of function to return the Z value difference between two geometries right? Could someone please point me in that direction? Thanks, Matthew
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