Hi. --- In [email protected], "davor_petric" <[EMAIL PROTECTED]> wrote: > This is the WRONG RESULT! Both calculations shouls show the same > result. May be a difference in the number of decimal places only. My > point was that the % seems to return a FALSE RESULT (but not always!?) > > Mod is the reminder after a divison shown in the integer format. So, > if I form an expression as: expr (20/3 ++ "." ++ 20%3) I should get > the same result as float.division (20,3): 6.6666 and not 6.2!
Nope. 20%3 is definitely 2 (20 - 6 * 3), i.e. the _remainder_ after dividing 20 by 3. Now, when you divide that remainder by 6 again, you get your 0,6667. Mockey Attention: PowerPro's Web site has moved: http://www.ppro.org Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/power-pro/ <*> To unsubscribe from this group, send an email to: [EMAIL PROTECTED] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/
