> replace(g)/match(g) function returns (sort of) error-codes, not the > resulting string/matches which is instead returned to the PP's > (user-specified) variable result_var. In replaceg case, however, there > is already a work-around, rg function. So, > > sString[patten] = replace > could call > regex.rg(sString,patten,replace)
On second reading, I realized you might mean: regex.replaceg(sString,patten,replace,"sString") Sean ------------------------ Yahoo! Groups Sponsor --------------------~--> You can search right from your browser? It's easy and it's free. See how. http://us.click.yahoo.com/_7bhrC/NGxNAA/yQLSAA/JV_rlB/TM --------------------------------------------------------------------~-> Attention: PowerPro's Web site has moved: http://www.ppro.org Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/power-pro/ <*> To unsubscribe from this group, send an email to: [EMAIL PROTECTED] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/
