> maybe in ByteBlock case:
> 263 = 272 - 6 - 4 + 1
> where 6 is the byteblock's overhead, and 4 may be terminating null in
>  unicode string case and among them 1 may be counted again as the
> (plain) terminating null character.

Sorry, I think I counted wrongly here. I don't know why I counted 4,
not 2 with the unicode string. Hmm, then, I don't know why it's 263.
Alan may answer it if he reads this thread.

Sean





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