Hi,
 
> for (local i=0; i<v.length; )  //must recompute v.length, no i++
> if (find(v[i],"Trigger2") > -1) do
> v.delete(i)  // shifts all elements down, so  look at new v[i] next
> else
> i++
> endif
> endfor

i like trying to reduce code to a minimum, if the result still remains somehow 
understandable. 

for(local i=v.length-1; i>=0; i--) 
   if(find(v[i],"Trigger2") > -1)
      v.delete(i)
endfor

p.s.
Could this also be done with regex ?

Best regards Detlef


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