Hi, > for (local i=0; i<v.length; ) //must recompute v.length, no i++ > if (find(v[i],"Trigger2") > -1) do > v.delete(i) // shifts all elements down, so look at new v[i] next > else > i++ > endif > endfor
i like trying to reduce code to a minimum, if the result still remains somehow
understandable.
for(local i=v.length-1; i>=0; i--)
if(find(v[i],"Trigger2") > -1)
v.delete(i)
endfor
p.s.
Could this also be done with regex ?
Best regards Detlef
