> > But works nicely when used the middle of the new multiline string assignment >
(BTW, multi-line strings can be used in any statement, not just assignments). local x = "end" local y = ???end alpha &(x) more end Works. This is because ??? processing happens as part of the initial reading of the statement. It is in fact implemented as a form of line continuation (similar to ;;+), and the ??? is translated into a standard ?x...x where x is a control character <0x20. But local x ="*" local y = ?*one&(x)two* fails with error message. If you understand why, then you have a good handle on &(). The order is 1. assemble statement and continuations, treating ???delim as a continuation which is translated to a ?..? which \rs inserted (you cannot do this yourself with normall ?x..x -- a trick is used internally). 2. Process all &(). 3. Now process the resulting statement using expression syntax.
