Thanks peter it worked. Can you confirm are the following way are the right way to write it? "msg4.actions.append(of.ofp_action_output(port = 0xfff8))" "msg4.actions.append(of.ofp_action_output(port = of.OFPP_IN_PORT))"
because this has worked for me but after installing this rule i.e. packet is going back from input port only but I am getting an error from on POX. I am getting this error when a switch tried to install a rule for the same packet which we have redirected through the in_port rule we discussed above. So i am in doubt that is the error occurred because I have written this "(port = 0xfff8) or (port = of.OFPP_IN_PORT)" in wrong way. Or this error is not related to this at all. Thanks and Regards. On Tue, Mar 3, 2015 at 7:09 PM, Peter Peresini <peter.peres...@epfl.ch> wrote: > Hi, > if you want to send packet back the same port, you need to explicitely > use OFPP_IN_PORT as a port number. This is to prevent packets looping in > the network as usually sending packets back is a bad idea (i.e., the peer > switch would probably send the packet again to us) > > Peter > > On Tue, Mar 3, 2015 at 2:35 PM, chaitanya tanwar < > chaitanya.tan...@gmail.com> wrote: > >> Hello everyone, >> >> Lets say we have switch s1, connected to h1 through port 1 and connected >> to s2 through port 2. >> >> As a packet arrives at port 2 from s2 to s1. I am modifying its >> destination mac and ip addresses and sending that back from the same port >> i.e. output port 2. >> >> But wireshark is not showing the same. Packet is arriving at port 2 from >> s2 to s1 but not going anywhere after that. >> >> Is there any trivial problem in sending the packet back through same port >> from where it has arrived? >> Because I have tried the same thing but sending the packet to port 1 and >> this time packet is going to port 1 but in case where I am sending it back >> through same port, Its not happening. >> >> Best Regards. >> > >
