Lindsay,
Well of course the expression
111
Is 100% made up of 1s.......
Good answer and of course you could use an identifier
containing lots of ls lots of time to get any desired
percentage.
To make life interesting we need a new rule:
Identifiers can only be one character long.
L.
Sent from my iPhone
On 28 Aug 2009, at 19:39, "Derek M Jones" <de...@knosof.co.uk> wrote:
Frank,
What about thinking up symmetric expressions, e.g.,
(p)++|++(q)
or:
l<-o->l
Anybody got some more eye twisters?
or trying to figure out how how to write the expression
containing the highest percentage of any character. For
instance, a ( or ) each make up 3/7 of the following
expression.
(((a)))
I know of one expression that is made up of 2/3 of one
particular character.
Can anybody do better?
All of the above are syntactically correct (well at last
after adding a semicolon and and enclosing function definition
and it is possible to create declarations for the variables to
make them acceptable to a strictly conforming C/C++ translator.
--
Derek M. Jones tel: +44 (0) 1252 520 667
Knowledge Software Ltd mailto:de...@knosof.co.uk
Source code analysis http://www.knosof.co.uk
--
Derek M. Jones tel: +44 (0) 1252 520 667
Knowledge Software Ltd mailto:de...@knosof.co.uk
Source code analysis http://www.knosof.co.uk
