On Tue, 14 Sep 2004 09:25:49 -0700 (PDT), jaya subba reddy
<[EMAIL PROTECTED]> wrote:
> 
>  
> I am sending my view which is related to the mersenne prime numbers. 
[snip]

The main idea seems to be that 3 log 10 is approximately 10 log 2.

Jaya, to find the number of decimal digits in 2^n (integer n >= 0),
use logarithms (pardon the Matlabese):

d = floor( log(2) / log(10) * n ) + 1
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