I searched the web for the starting numbers and found a japanese page with a better description of the algorithm (http://web2.incl.ne.jp/yaoki/2seqp2.htm)
Problem: A(n+1)=A(n)+B(n) B(n+1)=A(n)*B(n) A(1)=B(1)=1 Problem 1: General term A (n), B (n) please ask. (dunno what this one means) Problem 2: A(1)=1,A(2)=2,A(3)=3,A(4)=5 A(5)=11,A(6)=41,A(7)=371,A(8)=13901 B(1)=1,B(2)=1,B(3)=2,B(4)=6 B(5)=30,B(6)=330,B(7)=13530,B(8)=5019630 Prove for 'A (n) * B (n) +1' the fact that it becomes prime. --- Christian _______________________________________________ Prime mailing list [email protected] http://hogranch.com/mailman/listinfo/prime
