Hello, as you can see
A + B + C + D + E < 5 A so B.C.D.E < 5 with E >=1, D >= 2, C >= 3, and B>=4, it is possible to conclude 24 <= B.C.D.E < 5 and there are no solution to this problem (if I have undersood it correctly) Best regards, Denis ----- Original Message ----- From: "John R Pierce" <[EMAIL PROTECTED]> To: "The Great Internet Mersenne Prime Search list" <[email protected]> Sent: Wednesday, September 05, 2007 9:39 PM Subject: [Prime] [Fwd: Re: Finding large prime numbers] > George sent me two replies, as follows... > > > > -------- Original Message -------- > > I'm conversant with the fact that one needs to find and PROVE that a > number of 10,000,000 digits or more is prime and the way my sequence > generate primes probably makes it much easier to prove that the > numbers it generates are primes. > > Best regards, > > George > > > > -------- Original Message -------- > > If you can solve A + B + C + D + E = A x B x C x D x E where A > B > > C > D > E > 0, then you'll be part way into how I generate large > prime numbers. I apologize for the x notation for multiplication but > I don't know how to access all the special symbols on my computer > keyboard. And I've read the contest rules. > > Best regards, > > George S. Louis, CEO > Digital Systems & Solutions > > _______________________________________________ > Prime mailing list > [email protected] > http://hogranch.com/mailman/listinfo/prime > _______________________________________________ Prime mailing list [email protected] http://hogranch.com/mailman/listinfo/prime
