Gene Wirchenko wrote on 2013-09-26:
>> Look at the MemberClass and MemberClassLibrary of the grid to use your
>> subclass of Column.
>> On the Column will ADD OBJECT what you want, you can define the
HeaderClass
>> and HeaderClassLibrary
>
> This appears to me to imply that one is expected to have only
> one type of input control on a grid. What would happen if I wanted a
> textbox subclass and an editbox subclass (which I might well)? Would
> I have to go back to that kludge for the second subclass?
>
Gene,
You can have multiple.
You can do at design time as seen below. Or you can do it at runtime by
changing the MemberClass* properties then increasing the column count.
Tracy Pearson
PowerChurch Software
LOCAL loForm
loForm = CREATEOBJECT("testform")
loForm.AddObject("grd", "grd")
loForm.grd.visible = .T.
loForm.Show(1)
RELEASE loForm
CLEAR CLASS "testform"
DEFINE CLASS testform as Form
width = 400
height = 400
datasession = 2
PROCEDURE load
CREATE CURSOR testdata ( ;
ikey i, ;
cone c(10), ;
itwo i)
INDEX ON ikey TAG ikey
INDEX on itwo TAG itwo
INSERT INTO testdata ;
VALUES (1, "one", 1)
INSERT INTO testdata ;
VALUES (2, "three", 3)
INSERT INTO testdata ;
VALUES (3, "two", 2)
ENDPROC
ENDDEFINE
DEFINE CLASS grd as grid
top = 10
left = 10
width = 380
height = 380
rowsource = "testdata"
rowsourcetype = 1
anchor = 15
AllowCellSelection = .F.
recordmark = .f.
deletemark = .f.
splitbar = .f.
memberclasslibrary = "prggridform.prg"
memberclass = "clm"
*-- It is important to set this AFTER memberclass*
columncount = 2
memberclass = "clmchk"
columncount = 3
PROCEDURE init
this.clm1.controlsource = "testdata.cone"
this.clm1.header1.caption = "One"
this.clm2.controlsource = "testdata.itwo"
this.clm2.header1.caption = "Two"
ENDPROC
PROCEDURE DblClick
ThisForm.Release()
ENDPROC
ENDDEFINE
DEFINE CLASS clm as Column
ADD OBJECT txt as txt
sparse = .F.
ENDDEFINE
DEFINE CLASS clmchk as Column
ADD OBJECT chk as checkbox
sparse = .F.
ENDDEFINE
DEFINE CLASS txt as TextBox
forecolor = RGB(255,0,255)
ENDDEFINE
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