Hi wOOdy
Thanks for both your replies. I am not sure if it can be done at all
using VBScript.RegExp but it would be nice if it could. Your AcidTest
function has a problem with cDummy ...
Paul
On 12/12/2022 13:42, Jürgen Wondzinski wrote:
Hi Paul,
this would be a pure VFP solution:
**********************************************
? AcidTest("Methionine = (S)-2-amino-4-(methylsulfanyl)-butanoic acid (2.13)")
? AcidTest("Methionine = (S)-2-amino-4-(methylsulfanyl)-butanoic acid")
FUNCTION AcidTest(cText)
LOCAL cResult, nCount
nCount = OCCURS("(", cText)
cResult = STREXTRACT(cText, "(", ")", nCount)
IF LEN(CHRTRAN(cDummy, "0123456789.", "")) # 0
cResult ="FAIL"
EndIf
Return cResult
**********************************************
wOOdy
-----Ursprüngliche Nachricht-----
Von: ProFox <profox-boun...@leafe.com> Im Auftrag von Paul Newton
Gesendet: Montag, 12. Dezember 2022 14:10
An: profox@leafe.com
Betreff: Help with a regular expression
Hi all
I've been very quiet for a while so I thought it was about time I chimed in
again. I have come across the use of a regex expression in another language
which works like this:
acid1 = "Methionine = (S)-2-amino-4-(methylsulfanyl)-butanoic acid (2.13)"
acid2 = "Methionine = (S)-2-amino-4-(methylsulfanyl)-butanoic acid"
NumberAtEnd:= proc(S::string)
description
"Extract a parenthesized number, possibly containing periods, from the end of
a string":
local r;
if StringTools:-RegMatch("\\(([0-9.]*)\\)$", S, r$2) then r else FAIL fi
end proc:
NumberAtEnd(acid1) returns "2.13"
NumberAtEnd(acid2) returns "FAIL"
How can this be done in VFP? Many thanks
Paul Newton
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