On 1/23/07, Alan Bourke <[EMAIL PROTECTED]> wrote:
>
> A day is 6am to 6am (not 6pm like my original post, sorry) therefore the
> above uses up one day since it is within a 6am-6am timespan.
>

So,

#DEFINE SecondsInADay 24*3600
Function DaysUsed(tStartDateTime, tEndDateTime)
Return 1+INT((tEndDateTime-tStartDateTime)/SecondsInADay)

-- 
Ted Roche
Ted Roche & Associates, LLC
http://www.tedroche.com


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