Paul Newton wrote:
> No takers ?  OK is there a general solution to this type of problem:
>
> Four counters (Red, Green, Blue, Yellow)
> 24 distinct ways of arranging them.
> 1 correct arrangement (say Red, Green, Blue, Yellow)
> How are the incorrect arrangements distributed (what is the probablity 
> distribution of the incorrect arrangements) based on numer of counters 
> in the wrong position ?
>
> For five counters ?
>
> For n counters ?
>   
Hi Paul,

We used to do stuff similar to this on my degree course (Applied 
statistics and computing) but that finished in 1991 and I've slept since 
then, so can't remember most of it.  There used to be formulas for 
calculating these probabilities and I remember them using factorials but 
that's about it.

Do you have any ideas on this?

Peter



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