Jaime Vasquez wrote:
> Vince Teachout writes:
>
>> This is a little hard to explain, but I need to get a count of distinct
>> codes within orders. For example:
>>
>> Order 1:
>> code1
>> Code 1
>> code 1
>> code 2
>> code 3
>>
>> Order 2:
>> code 1
>> Code 3
>>
>> I'd like to see:
>> "Code 1", 2
>> "Code 2", 1
>> "Code 3, 2
>>
>> ie, distinct within orders, but then a count of codes for all orders.
>> Anyway to do it in one shot? I'm pretty sure I can do it in 2 queries.
>> Thanks.
>
>
> create cursor codes (order1 char(10), code char(10))
>
> insert into codes values("Order 1", "code 1")
> insert into codes values("Order 1", "code 1")
> insert into codes values("Order 1", "code 1")
> insert into codes values("Order 1", "code 2")
> insert into codes values("Order 1", "code 3")
> insert into codes values("Order 2", "code 1")
> insert into codes values("Order 2", "code 3")
>
>
> select code, count(code) from codes group by code
No, because I'm trying to get Count( distinct codes), so I'd want to see
the results posted above. Your example just gives me a straight count:
code 1, 4
code 2, 1
code 3, 2
I've already done it using 2 selects, was just curious about doing it in
one. Thank you, though.
--
Vince Teachout
Caracal Software
www.caracal.net
518-733-9411
_______________________________________________
Post Messages to: [email protected]
Subscription Maintenance: http://leafe.com/mailman/listinfo/profox
OT-free version of this list: http://leafe.com/mailman/listinfo/profoxtech
Searchable Archive: http://leafe.com/archives/search/profox
This message: http://leafe.com/archives/byMID/profox/[EMAIL PROTECTED]
** All postings, unless explicitly stated otherwise, are the opinions of the
author, and do not constitute legal or medical advice. This statement is added
to the messages for those lawyers who are too stupid to see the obvious.
