The options field value is using bit flags... so just break the 
option # you are using into it's proper pieces for each bit value.

131609 = 131072+512+16+8+1

This is equivalent to a number where the bits 17,9,4,3,0 are set.

Looking at the MyODBC reference this is equivalent to:

FLAG_SAFE + FLAG_PAD_SPACE + FLAG_NO_PROMPT + FLAG_BIG_PACKETS + 
FLAG_FIELD_LENGTH

At 08:28 AM 9/13/2007, you wrote:
>Eugene Vital wrote:
> >>> This is the specific setting that affects it.
> >>>
> >>> 16384       |FLAG_NO_BIGINT|        Change BIGINT Columns to 
> Int    Change |BIGINT|
> >>> columns to |INT| columns (some applications can't handle |BIGINT|).
> >>>
> >>>
> >>>
> >>>
> >> I just wish it were easy to see the compilations of the different values
> >> to come up with that final magic number.
> >>
> >>
> >>
> > Well in this case, 16384 there is no compilation that would add up to
> > that number.
> >
> > There is only one way to achieve the 16899, 16384 + 512 + 2 + 1
> >
>
>I'm not using any BIGINT columns...INT works just fine for me...so I'm
>curious as to what other flags I was using in my 131609 value.
>
>--
>Michael J. Babcock, MCP
>MB Software Solutions, LLC
>http://mbsoftwaresolutions.com
>http://fabmate.com
>"Work smarter, not harder, with MBSS custom software solutions!"
>
>
>
[excessive quoting removed by server]

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