1. When using a report listener, the FRX is open in a different datasession
(ID stored in ReportListener.FRXDataSession). In addition, several methods
in the report listener have nFRXRecno as a parameter which is the record
number in the FRX. So any time you want to access properties of an object,
do something like this:
SET DATASESSION TO FRXDataSession
GOTO nFRXRecNo
** Look at whatever fields you want
SET DATASESSION TO CurrentDataSession
2. To get the properties of a picture ...
*-- Create an image object
This.AddProperty('oImage', ;
NEWOBJECT('gpImage', HOME() + 'FFC\_GDIPLUS'))
*-- Create the image
This.oImage.CreateFromFile("FileNameHere")
*-- Get the picture width and height
lnActPictWidth = This.oImage.ImageWidth
lnActPictHeight = This.oImage.ImageHeight
3. To adjust the left position, you can use the Render method. One of the
parameters it passes is the Left. Issue a NODEFAULT .. and then
DODEFAULT(..parameter list) .. but substitute whatever you want for the left
property when you use the DODEFAULT.
I hope this helps,
Cathy
> -----Original Message-----
> From: [email protected] [mailto:[email protected]]
On
> Behalf Of Joe Yoder
> Sent: Wednesday, February 25, 2009 1:26 AM
> To: [email protected]
> Subject: Centering a picture on a report
>
> I'm working on a report with a photo at the top of each page. The photo
> files are all .jpgs but some are landscape and some are portrait
> orientation. I need to hold the original aspect ratio of the photo to
> avoid distortion (Scale contents but Retain shape.) The picture box on
the
> report is in landscape orientation. When a photo with portrait
orientation
> is rendered it is positioned to have its left edge line up with the left
> edge of the picture box on the report. I want to change the left bound of
> the picture box on the fly based on the aspect ratio of the picture being
> printed to cause the picture to be centered above its caption.
>
> I understand it is possible to do this sort of thing with report listeners
> but haven't figured out how to access the properties of the objects on the
> report. Another thing I will need is a way to find the width and height
of
> the photo. I assume this is probably available via an API but maybe VFP
> has functions to do it as well.
>
> Thanks in advance for any help!
>
> Joe Yoder
>
>
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> ---
>
[excessive quoting removed by server]
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