Hi Tracy

Ok, I will take look at that in a moment.(US OPEN)
value 3;
as table1x is 2 it inherits all from value 2(4 and 5), 
but value 2 inherits from 1 because table1x being 1( 1,2,3) 
and 6 from table3.
So the result for value 3 is (1,2,3,4,5,6).

Thanks, E.

CREATE CURSOR table2 (table1 I, table1x I, table3 I)   
insert into table2(table1, table1x, table3) values(1,0,1)   
insert into table2(table1, table1x, table3) values(1,0,2)   
insert into table2(table1, table1x, table3) values(1,0,3)   
insert into table2(table1, table1x, table3) values(2,0,4)   
insert into table2(table1, table1x, table3) values(2,1,0)   
insert into table2(table1, table1x, table3) values(2,0,5)   
insert into table2(table1, table1x, table3) values(3,2,0)   
insert into table2(table1, table1x, table3) values(3,0,6)   



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