How about
lday=DAY(CTOD("01/03/"+ALLTRIM(STR(YEAR(DATE()))))-1)
On Wed, Apr 13, 2011 at 10:08 AM, Paul McNett <[email protected]> wrote:
> On 4/12/11 2:56 PM, Ed Leafe wrote:
> > import calendar
> > return calendar.isleap(year)
>
> Hmm, looking at the source, at least in Python 2.6.5, I think the isleap()
> function
> isn't as efficient as it could be. But it is one line. Here it is,
> converted to VFP
> if anyone wants it:
>
> {{{
>
> FUNC isleap(nYear):
> RETURN m.nYear % 4 == 0 AND (m.nYear % 100 != 0 OR m.nYear % 400 == 0)
>
> }}}
>
> Paul
>
[excessive quoting removed by server]
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