El código parece que esta bien.
Quizás tenés el archivo abierto o tuvo algún error al crear el archivo.
Ponele un "if" para verificar si fopen. Tendrías que usar fclose si no
te devuelve NULL.
Copy-pastié tu código y le corrí el valgrind.
Mira el detalle de errores corriendo valgrind con "-v".
Esta es la respuesta que valgrind me tiro a mi:
==13622== Memcheck, a memory error detector.
==13622== Copyright (C) 2002-2007, and GNU GPL'd, by Julian Seward et
al.
==13622== Using LibVEX rev 1732, a library for dynamic binary
translation.
==13622== Copyright (C) 2004-2007, and GNU GPL'd, by OpenWorks LLP.
==13622== Using valgrind-3.2.3-Debian, a dynamic binary instrumentation
framework.
==13622== Copyright (C) 2000-2007, and GNU GPL'd, by Julian Seward et
al.
==13622== For more details, rerun with: -v
==13622==
==13622==
==13622== ERROR SUMMARY: 0 errors from 0 contexts (suppressed: 11 from
1)
==13622== malloc/free: in use at exit: 0 bytes in 0 blocks.
==13622== malloc/free: 1,387 allocs, 1,387 frees, 64,390 bytes
allocated.
==13622== For counts of detected errors, rerun with: -v
==13622== All heap blocks were freed -- no leaks are possible.
El mié, 19-03-2008 a las 10:33 -0300, Federico De Seta escribió:
> Hola!. Tengo el siguiente programa:
>
>
> #include <stdio.h>
> #include "stdlib.h"
>
> typedef struct{
> int nro;
> char letra;
> }campo;
>
> int main(int argc, char ** argv)
> {
> campo *reg1 = (campo*)malloc (sizeof(campo));
> reg1->nro = 5 ;
> reg1->letra ='g';
> FILE* p = fopen("lala.txt", "wb");
>
> fwrite((void*)reg1, sizeof(campo), 1, p);
> fclose(p);
> free(reg1);
> return (0);
> }
>
> Cuando lo corro con el valgrind me tira lo siguiente:
>
>
> ==6248== Memcheck, a memory error detector.
> ==6248== Copyright (C) 2002-2007, and GNU GPL'd, by Julian Seward et
> al.
> ==6248== Using LibVEX rev 1804, a library for dynamic binary
> translation.
> ==6248== Copyright (C) 2004-2007, and GNU GPL'd, by OpenWorks LLP.
> ==6248== Using valgrind-3.3.0, a dynamic binary instrumentation
> framework.
> ==6248== Copyright (C) 2000-2007, and GNU GPL'd, by Julian Seward et
> al.
> ==6248== For more details, rerun with: -v
> ==6248==
> ==6248== Syscall param write(buf) points to uninitialised byte(s)
> ==6248== at 0x40E95C3: __write_nocancel
> (in /lib/tls/i686/cmov/libc-2.3.6.so)==6248== by 0x408CC8A:
> _IO_do_write@@GLIBC_2.1 (in /lib/tls/i686/cmov/libc-2.3.6.so)
> ==6248== by 0x408C3D4: _IO_file_close_it@@GLIBC_2.1
> (in /lib/tls/i686/cmov/libc-2.3.6.so)
> ==6248== by 0x408281A: fclose@@GLIBC_2.1
> (in /lib/tls/i686/cmov/libc-2.3.6.so)
> ==6248== by 0x80484AB: main (main.c:21)
> ==6248== Address 0x4021005 is not stack'd, malloc'd or (recently)
> free'd
> ==6248==
> ==6248== ERROR SUMMARY: 1 errors from 1 contexts (suppressed: 11 from
> 1)
> ==6248== malloc/free: in use at exit: 0 bytes in 0 blocks.
> ==6248== malloc/free: 2 allocs, 2 frees, 360 bytes allocated.
> ==6248== For counts of detected errors, rerun with: -v
> ==6248== All heap blocks were freed -- no leaks are possible.
>
>
> La linea 21 del main es la del fclose. Alguien sabe que puede ser?
>
> Saludos y gracias de antemano por responder.
>
> Fd.
>
>
>
>
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