teman-teman terima kasih sudah selesai masalahnya regards nyoman
--- In [email protected], "Nyoman Darsana" <dars...@...> wrote: > > apa kira2 ini bisa digunakan ? > > if (a^b) > c then > sisanya=(a ^ b) mod c > else > sisanya=(a^b) > endif > > > salam, > nyom2 > > ----- Original Message ----- > From: gunartha > To: [email protected] > Sent: Tuesday, May 18, 2010 11:12 AM > Subject: [programmer-vb] Re: mencari sisa pembagian > > > > Teman-teman, > Terima kasih tanggapannya, setelah saya goolge saya dapat contoh > penyelesainnya seperti di bawah : > x = (4 ^ 13) mode 497 > x = 445 > > kira-kira kalau dalam bahasa VB nya gimana ya ? > > The example b = 4, e = 13, and m = 497 is presented again. The algorithm > passes through step 3 thirteen > times: > e' = 1. c = (1 * 4) mod 497 = 4 mod 497 = 4. > e' = 2. c = (4 * 4) mod 497 = 16 mod 497 = 16. > e' = 3. c = (16 * 4) mod 497 = 64 mod 497 = 64. > e' = 4. c = (64 * 4) mod 497 = 256 mod 497 = 256. > e' = 5. c = (256 * 4) mod 497 = 1024 mod 497 = 30. > e' = 6. c = (30 * 4) mod 497 = 120 mod 497 = 120. > e' = 7. c = (120 * 4) mod 497 = 480 mod 497 = 480. > e' = 8. c = (480 * 4) mod 497 = 1920 mod 497 = 429. > e' = 9. c = (429 * 4) mod 497 = 1716 mod 497 = 225. > e' = 10. c = (225 * 4) mod 497 = 900 mod 497 = 403. > e' = 11. c = (403 * 4) mod 497 = 1612 mod 497 = 121. > e' = 12. c = (121 * 4) mod 497 = 484 mod 497 = 484. > e' = 13. c = (484 * 4) mod 497 = 1936 mod 497 = 445. > The final answer for c is therefore 445, as in the first method. > > --- In [email protected], Sigit <p_cgate@> wrote: > > > > ni cman kira2 aja.. > > x= 729^78 > > y= x mod 3335 > > > > On 18/05/2010 7:26, gunartha wrote: > > > > > > Yth VBier, > > > > > > Mohon bantuannya saya punya masalah dengan hasil pangkat yg besar dan di > > > mod kan. > > > Contoh begini : > > > saya mau mencari nilai x adalah sisa hasil pembagian dari : > > > x = (729 ^ 78) mod 3335 > > > > > > kenapa muncul erorr "stack overflow" > > > > > > Terima kasih > > > regards > > > gunartha > > > > > > > > > > > >
