Would this definition work for monadic case?

   oo_explicated=: 3 : 0
        NB. ((+/) % #) @ ((,&1)"1)
u=: 3 : '(+/ y) % (# y)'        NB. [rank: _ _ _]   (+/) % #
v=: (3 : 'y , 1')"1             NB. [rank: 1 1 1]   (,&1)"1
u"v v y
)
   oo_explicated i. 3 4
1.4 4.6 7.8


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