Kindergarten class... I have a list of boxed literals... z=: 'alpha' ; 'bravo' ; 'charlie'
I want to flatten it to a literal, but with spaces between. (Variant: --with LF's). Raze (;) does indeed flatten the list... ;z alphabravocharlie There's got to be a really neat extended Raze which includes separators. But the fastest I've been able to come up with is: b2o=: }.@((<' ') ;@,. ]) b2o z alpha bravo charlie Any advances? ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
