h=: 13 :';x([:<(,"1}.)"1#~(([:={:) |.)"1)"1 _ y'
A h B
|domain error: h
| A h B
h
[: ; ([: < (,"1 }.)"1 #~ (([: = {:) |.)"1)"1 _
Here’s what I really want:
i=: ; ([: < (,"1 }.)"1 #~ ([:={: |.)"1)"1 _
A i B
|domain error: i
| i
; ([: < (,"1 }.)"1 #~ ([: (= {: |.))"1)"1 _
A i B
5!:4 <'i'
┌─ ;
│ ┌─ [:
│ ├─ <
│ │ ┌─ ,
│ │ ┌─ " ─┴─ 1
──┤ ┌─────┤ ┌───┴─ }.
│ │ │ ┌─ " ─┴─ 1
│ │ │ │
│ │ │ ├─ ~ ─── #
│ │ └────┤ ┌─ [:
└─ " ─┤ │ ┌───┤ ┌─ =
│ │ │ └─────┼─ {:
│ └─ " ─┤ └─ |.
│ └─ 1
└─ 1 _
But ii is what I really want to work:
ii=: ; ([: < (,"1 }.)"1 #~ ([:={: |.))"1)"1 _
|syntax error
| ii=:;([:<(,"1}.)"1#~([:={:|.))"1)"1 _
ii
; ([: < (,"1 }.)"1 #~ ([: (= {: |.)))"1
5!:4 <'ii'
┌─ ;
│ ┌─ [:
│ ├─ <
│ │ ┌─ ,
│ │ ┌─ " ─┴─ 1
──┤ ┌───┤ ┌────┴─ }.
│ │ │ ┌─ " ─┴─ 1
│ │ │ │
│ │ │ ├─ ~ ─── #
│ │ └────┤
└─ " ─┤ │ ┌─ [:
│ └─────┤ ┌─ =
│ └────┼─ {:
│ └─ |.
└─ 1
I think the tree lools wrong, as it should be a fork not a hook.
Linda
-----Original Message-----
From: programming-boun...@forums.jsoftware.com
[mailto:programming-boun...@forums.jsoftware.com] On Behalf Of Raul Miller
Sent: Saturday, October 20, 2012 12:19 PM
To: programm...@jsoftware.com
Subject: Re: [Jprogramming] stitching matrices
If you actually wanted to only be using monadic definitions for f and g, these
would be equivalent definitions:
f=: =&{: :[:
g=: ([:={:) :[:
Here, you would be declaring that these verbs have empty dyadic domains.
You could even get away with
g=: [:={: :[:
(Do you see why?)
--
Raul
On Sat, Oct 20, 2012 at 2:57 AM, Linda Alvord <lindaalv...@verizon.net> wrote:
> I am using them monadically.
>
> Linda
>
> -----Original Message-----
> From: programming-boun...@forums.jsoftware.com
> [mailto:programming-boun...@forums.jsoftware.com] On Behalf Of km
> Sent: Saturday, October 20, 2012 2:54 AM
> To: programm...@jsoftware.com
> Subject: Re: [Jprogramming] stitching matrices
>
> Identical?
>
> f =: =&{:
> g =: [:={:
> 1 4 f 2 3 4
> 1
> 1 4 g 2 3 4
> |domain error: g
> | 1 4 g 2 3 4
>
> Kip Murray
>
> Sent from my iPad
>
>
> On Oct 20, 2012, at 1:11 AM, "Linda Alvord" <lindaalv...@verizon.net> wrote:
>
>> Here's a problem that bothers me about this example before I leave it.
>>
>>
>>
>> First establish that =&{: and [:={: are identical and compare
>> tree and boxed versions:
>>
>>
>>
>>
>>
>> ]'A B'=:3|L:0(([:<i.)"1)3 5,:5 4
>>
>> ----------T-------┐
>> │0 1 2 0 1│0 1 2 0│
>> │2 0 1 2 0│1 2 0 1│
>> │1 2 0 1 2│2 0 1 2│
>> │ │0 1 2 0│
>> │ │1 2 0 1│
>> L---------+--------
>>
>> f=:=&{:
>>
>> g=:[:={:
>>
>> 5!:4 <'f'
>>
>> -- =
>> -- & -+- {:
>>
>> 5!:4 <'g'
>>
>> -- [:
>> --+- =
>> L- {:
>>
>> B
>>
>> 0 1 2 0
>> 1 2 0 1
>> 2 0 1 2
>> 0 1 2 0
>> 1 2 0 1
>>
>> f B
>>
>> 1 0 0 1
>> 0 1 0 0
>> 0 0 1 0
>>
>> g B
>>
>> 1 0 0 1
>> 0 1 0 0
>> 0 0 1 0
>>
>>
>>
>> Now look at two "trees":
>>
>>
>>
>> elm=: 13 :'((=&{:)|.)"1 y'
>>
>> oak=: 13 :'(([:={:)|.)"1 y'
>>
>> 5!:4 <'elm'
>>
>> -- =
>> -- & -+- {:
>> ----+- |.
>> -- " -+- 1
>>
>> 5!:4 <'oak'
>>
>> -- [:
>> -----+- =
>> ----+ L- {:
>> -- " -+ L- |.
>> L- 1
>>
>> 5!:2 <'elm'
>>
>> --------------T-T-┐
>> │---------T--┐│"│1│
>> ││--T-T--┐│|.││ │ │
>> │││=│&│{:││ ││ │ │
>> ││L-+-+---│ ││ │ │
>> │L--------+---│ │ │
>> L-------------+-+--
>>
>> 5!:2 <'oak'
>>
>> ---------------T-T-┐
>> │----------T--┐│"│1│
>> ││---T-T--┐│|.││ │ │
>> │││[:│=│{:││ ││ │ │
>> ││L--+-+---│ ││ │ │
>> │L---------+---│ │ │
>> L--------------+-+--
>>
>> B
>>
>> 0 1 2 0
>> 1 2 0 1
>> 2 0 1 2
>> 0 1 2 0
>> 1 2 0 1
>>
>> elm B
>>
>> 1 1 1 1 1
>>
>> oak B
>>
>> ran with error:
>> |domain error: oak
>> | oak B
>> |[-16] c:\users\owner\j701-user\temp\42.ijs
>>
>>
>>
>> I'm not troubled by the fact that these results are different. I am
>> bothered that their differences do not appear in the tree and boxed
>> version, because I expect them both to be elm trees!
>>
>>
>>
>> If these versions don't show any differences shouldn't the results
>> agree. I think the tree versions must be missing some way to tell them
>> apart.
>>
>>
>>
>> Any thoughts?
>>
>>
>>
>> Linda
>>
>>
>>
>> Linda
>>
>>
>>
>>
>>
>>
>>
>> -----Original Message-----
>>
>> From: <mailto:programming-boun...@forums.jsoftware.com>
>> programming-boun...@forums.jsoftware.com
>>
>> [ <mailto:programming-boun...@forums.jsoftware.com>
>> mailto:programming-boun...@forums.jsoftware.com] On Behalf Of Raul
>> Miller
>>
>> Sent: Friday, October 19, 2012 9:30 AM
>>
>> To: <mailto:programm...@jsoftware.com> programm...@jsoftware.com
>>
>> Subject: Re: [Jprogramming] stitching matrices
>>
>>
>>
>> On Fri, Oct 19, 2012 at 4:00 AM, Linda Alvord <
>> <mailto:lindaalv...@verizon.net> lindaalv...@verizon.net>
>>
>> wrote:
>>
>>> G B
>>
>>> 1 1 1 1 1
>>
>>> H B
>>
>>> ran with error:
>>
>>> |domain error: H
>>
>>> | H B
>>
>>> |[-30] c:\users\owner\j701-user\temp\37.ijs
>>
>>
>>> G WORKS! H DOESN'T!
>>
>>
>>> How can I write the function H without & and get 1 1 1 1 ?
>>
>>
>>
>> Here's G B
>>
>> ((=&{:)|.)"1 $~&5 4 i.3
>>
>> 1 1 1 1 1
>>
>>
>>
>> Here, I rephrase G by eliminating the &
>>
>> (({:@[ = {:@])|.)"1 $~&5 4 i.3
>>
>> 1 1 1 1 1
>>
>>
>>
>> Note that I am testing the result at each step, here, to make sure
>> I've not made any bad assumptions (for example, hypothetically
>> speaking some intermediate results in these kinds of transformations
>> might need some explicit treatment of rank).
>>
>>
>>
>> Here, I further rephrase G by also eliminating both of the @
>> conjunctions
>>
>> ((([: {: [) = ([: {: ]))|.)"1 $~&5 4 i.3
>>
>> 1 1 1 1 1
>>
>>
>>
>> Here, I simplify slightly by using a hook
>>
>> (((([: {: [) = ]) {:)|.)"1 $~&5 4 i.3
>>
>> 1 1 1 1 1
>>
>>
>>
>> Here, I simplify again by using a cross hook
>>
>> (((= {:)~ {:) |.)"1 $~&5 4 i.3
>>
>> 1 1 1 1 1
>>
>>
>>
>> Good enough?
>>
>>
>>
>> Thanks,
>>
>>
>>
>> --
>>
>> Raul
>>
>> ---------------------------------------------------------------------
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>>
>> For information about J forums see
>> <http://www.jsoftware.com/forums.htm>
>> http://www.jsoftware.com/forums.htm
>>
>>
>>
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>>
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>>
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