I was working with a friend on some curve fitting things and we were
plotting the results along with a single point that represented the
center of a circular fitting function. When trying to plot the single
point, we ran into this -
iMi7:~ jkt$ j64
JVERSION
Engine: j701/2011-01-10/11:25 build: Feb 6 2011 16:16:29
Library: 7.01.071
Platform: Darwin 64
Installer: j701a_mac64.dmg
InstallPath: /Applications/j64-701
load 'plot'
pd 'type point'
pd 2;2
pd 'show'
|length error: pdf_circle
| 'x y r' =.y
Doing the same thing, but using
pd (,2); ,2
worked as I expected, putting a single point at 2,2
I guess it is a bit unusual to want to plot a single point, but I think
it should work with scalars the same as with length 1 vectors...
Trying to poke at this a bit more, I tried -
iMi7:~ jkt$ j64
load 'plot'
pd i.5
pd 'show'
pd 'type point'
pd 2;3 4
pd 'show'
and that seemed to work, apparently extending the scalar 2 to be 2 2
BUT it also reverted the type on the line drawn by the pd i.5 to points,
that seems unexpected/wrong too.
Doing a similar experiment on iOS (iPad) didn't get the length error,
but did revert the line from pd i.5 to points after setting type point
and doing pd 2;3.
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