Ah. In that case there is a shorter computation: s=: 'abccdadba' +/ (#:}.i.2^#s) (-:|.)@# s 50
On Thu, Jan 10, 2013 at 10:42 AM, Don Guinn <dongu...@gmail.com> wrote: > Could they be counting duplicates? > > $ ~. (#~(-:|.)&>) 'abccdadba'<@:#"1~ }. #: i.2^9 > > 29 > > $ (#~(-:|.)&>) 'abccdadba'<@:#"1~ }. #: i.2^9 > > 50 > > > On Thu, Jan 10, 2013 at 11:39 AM, Roger Hui <rogerhui.can...@gmail.com > >wrote: > > > $ ~. (#~(-:|.)&>) 'abccdadba'<@:#"1~ }. #: i.2^9 > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm > ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
