Interrupting may be a bad idea.

   NB. -------- Use 13 : correctly.
   NB.    f=: 13 :',j./&i:/+.y'           NB. no.
   NB.    f=: 13 : '([: , j./&i:/@+.) y'  NB. yes.

   ic2 =: [: , j./&i:/@+.
   
   NB. Using a proverb is as if its definition
   NB. were inserted with parenthesis.
   NB. Copy ic2 definition verbatim,
   NB. Surround with parentheses.
   NB. Put in the arguments, then fix quotes.

   13 : '([: , j./&i:/@+.) y'
[: , j./&i:/@+.

   NB. The definition was tacit,
   NB. 13 : returns this tacit verb unchanged



   NB. -------- Equivalence of ic and ic2
   NB."However, I do not understand how ic and ic2 agree when they
don't!"
   
   ic =: [: , ([: i: 9&o.) j./ [: i: 11&o.

   ic2 =: [: , j./&i:/@+.

   NB. ic  and  ic2  are identical at rank 0
   (ic -: ic2)&>1j2 0j2
1 1

   ([: < ic)"0 ] 1j2 0j2
+----------------------------------------------------------------+-------------------+
|_1j_2 _1j_1 _1 _1j1 _1j2 0j_2 0j_1 0 0j1 0j2 1j_2 1j_1 1 1j1 1j2|0j_2
0j_1 0 0j1 0j2|
+----------------------------------------------------------------+-------------------+
   ([: < ic2)"0 ] 1j2 0j2
+----------------------------------------------------------------+-------------------+
|_1j_2 _1j_1 _1 _1j1 _1j2 0j_2 0j_1 0 0j1 0j2 1j_2 1j_1 1 1j1 1j2|0j_2
0j_1 0 0j1 0j2|
+----------------------------------------------------------------+-------------------+



>Date: Mon, 21 Jan 2013 03:58:24 -0500
>From: "Linda Alvord" <[email protected]>
>To: <[email protected]>
>Subject: Re: [Jprogramming] [Jprogrammingou Hermitian from triangular
>Message-ID: <001d01cdf7b5$78a4cd20$69ee6760$@net>
>Content-Type: text/plain;       charset="koi8-r"
>
>Since this has a mistake it is hard to reconstruct what I did wrong.
This
>represents what I was doing:
>
> 
>
>   ic2=: [: , j./&i:/@+.
>
>   ic2
>
>[: , j./&i:/@+.
>
>   ([: , j./&i:/@+.)2
>
>_2 _1 0 1 2
>
>   f=: 13 :',j./&i:/+.y'
>................
>
>   ic 1j2 0j2
>
>_1j_2 _1j_1 _1 _1j1 _1j2 _1j_2 _1j_1 _1 _1j1 _1j2 0j_2 0j_1 0 0j1 0j2
0j_2
>0j_1 0 0j1 0j2 1j_2 1j_1 1 1j1 1j2 1j_2 1j_1 1 1j1 1j2 0j_2 0j_1 0 0j1
0j2
>0j_2 0j_1 0 0j1 0j2 0j_2 0j_1 0 0j1 0j2 0j_2 0j_1 0 0j1 0j2 0j_2 0j_1 0
0j1
>0j2 0j_2 0j_1 0 0j1 0j2
>
>   
>
>   ic2 1j2 0j2
>
>_1j_2 _1j_1 _1 _1j1 _1j2 0j_2 0j_1 0 0j1 0j2 1j_2 1j_1 1 1j1 1j2 0j_2
0j_1 0
>0j1 0j2 0 0 0 0 0 0 0 0 0 0
>
>  
>
> (ic-:ic2)&>1j2 0j2
>
>1 1
>
>   
>
>However, I do not understand how ic and ic2 agree when they don't! 

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