This sounds sensible, but if you tested your code, you should notice two things:
First, 3 :'x,y' gives a domain error or a value error (depending on
context). To fix this you have several options:
You can remove the x -- probably not what you want.
You can change the 3 to a 4 -- probably the simplest and best option
for this case.
You can introduce the ':' line which separates the monadic from the
dyadic definition in an explicit verb -- probably overkill, but like
this: 3 :(':';x`:0 y')"0 _
That gets you something that runs.
But this should reveal a new issue: the behavior of 3 :'x`:0 y'"0 _
gives you the same kind of results that 3 :'x`:0 y' gives you. The
rank of the derived verb is different, but that's a subtle sort of
thing. There's also a variety of ways of treating this issue, but
most of them involve reducing the right rank of the derived verb
(probably using "0 or "0 _1, depending on exactly what you are trying
to achieve).
I hope this helps,
--
Raul
On Wed, Jan 23, 2013 at 2:43 PM, Marshall Lochbaum <[email protected]> wrote:
> I think you mean to apply each gerund to a corresponding item of the
> argument? In any case, I would suggest just making an apply verb
>
> apply =: 3 : 'x`:0 y' "0 _
>
> and applying it with the appropriate rank (_1 by my interpretation).
> Since you understand rank, this is a general solution to an entire class
> of problems.
>
> Marshall
>
> On Wed, Jan 23, 2013 at 06:29:00PM +0100, R.E. Boss wrote:
>> In <http://www.jsoftware.com/help/dictionary/d612.htm>
>> http://www.jsoftware.com/help/dictionary/d612.htm (`: n) is explained, but
>> how do I apply a set of gerunds to one set of items?
>>
>>
>>
>>
>>
>> R.E. Boss
>>
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