When I read it I thought the problem was to find the largest area as a function of the size of the existing barn wall. If size is zero or less then the area is (*:100%4); if it is (100%3) or larger the the area is (*:100%3); and the interesting part is in between. The function, I think, is:
(area=. (*:100%4) >. (*:100%3) <. 16 %~ *:@:(100&+)) 625 >. 1111.1111111111113 <. 16 %~ *:@:(100&+) load'plot' plot (];area) (i:50) On Sat, Feb 23, 2013 at 9:42 AM, km <k...@math.uh.edu> wrote: > Use J to solve the farmer's fence problem: > > A farmer with 100 meters of wire fence wants to make a rectangular chicken > yard using an existing barn wall for one of the north-south sides. What is > the largest area he can enclose if he uses the 100 meters of fence for the > other three sides, and what are the dimensions of the largest-area chicken > yard? > > Kip Murray > > Sent from my iPad > > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm > ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
