I happened to be reading
H. Frets and Scripts
http://www.jsoftware.com/help/dictionary/dicth.htm
and was trying to work out the example
s=: 0 : 0
y*%:y
:
x*!y
)
a. i. s The character with index 10 marks the end of
each line
121 46 42 37 58 121 46 10 58 10 120 46 42 33 121 46 10
when I was stumped trying find the four operators between two "y"s (The ASCII "121") in the monadic part of the script. (I'm not so fluent in the non-alphanumeric parts of the ASCII
table.) The answer seems to be that rather than just a "y", "121 46" is a representation of "y.", the former name of "y". (See 9!:48 and 9!:49.[1]) Similarly,
"x" in the example is represented by "120 46" (for "x."). I wonder if someone changed all occurrences of "y." to "y" and "x." to "x", but
in this case forgot to rerun the example to regenerate the document.
Running
9!:14 ''
j701/2011-01-10/11:25 build: Feb 6 2011 16:16:29
with
9!:48 ''
0
Copying the example, I see
a. i. s
121 42 37 58 121 10 58 10 120 42 33 121 10
where "y" is represented by a simple "121" without the trailing "46".
... peter
[1] http://www.jsoftware.com/help/dictionary/dx009.htm
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