Oh! I had not paid attention to $!.n
But, basically, it's similar to take ({.) - it uses y for any cells
specified there, and uses fill after that. (I had not paid attention
and thought that fill was only for the empty y case)
That said, given this behavior, I'm still not seeing why there should
be anything special about empty y for $!.n - we use n to specify the
fill, should it really matter that y was empty and the entire thing is
fill?
Taking a step back, the unadorned x$y case says that y is the data and
x is the shape, and it's an error if we have a non-empty shape but we
have not specified any data. The x$!.n y case is different because we
have specified the data - that spec is split across n and y, and n has
a special case handling if it's empty instead of being an atom. In
other words, it seems to me that the motivation for the 1$'' error is
absent from the 1$!.'' '' case.
You clearly have a different perspective on this from me, and it's
entirely possible that I've overlooked something else important for
this situation, but "I still don't get it".
Thanks,
--
Raul
On Tue, Apr 23, 2013 at 4:19 PM, Henry Rich <[email protected]> wrote:
> 5 $!.5 i. 3
> 0 1 2 5 5
>
> Henry Rich
>
>
> On 4/23/2013 4:17 PM, Raul Miller wrote:
>>
>> I am not following your reasoning here.
>>
>> Is there some way to have shape use fill that does not involve an empty y?
>>
>> Thanks,
>>
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