That's correct Raul, the formula solved    (k^n)>:10^93   rather than   
(k^n)>10^93   . (The devil is in the detail). -Bo.





>________________________________
> Fra: Raul Miller <rauldmil...@gmail.com>
>Til: Programming forum <programm...@jsoftware.com> 
>Sendt: 15:04 onsdag den 1. maj 2013
>Emne: Re: [Jprogramming] Transcomputational numbers
> 
>
>On Wed, May 1, 2013 at 2:02 AM, Bo Jacoby <bojac...@yahoo.dk> wrote:
>> If I understand the question correctly, the problem is to solve the 
>> inequality k^n>10^93 for integer n.
>..
>> 10  93
>
>(10^93) > 10^93 is probably false.
>
>-- 
>Raul
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