It occurs to me that a reasonable compromise would be

   onaxes =: 2 : 'u"(#n)&.(n&|:)'

where the number of axes gives the rank of u.

Henry Rich

On 5/31/2013 9:26 PM, Henry Rich wrote:
It looks to me like that's pretty close to working, except that you
always want to apply v to rows, i. e. rank 1, i. e.

    colOrRow =. 2 : ' v"1`(v"1 &.|:)@.m'

but now I must accuse you of incomplete generalization.  Suppose the
operand has higher rank?  Isn't what you really want to apply v along a
given axis?  And, come to think of it, shouldn't we allow v to have any
rank, and apply it to selected axes?  I would switch the meanings of u
and v, and write

    onaxes =: 2 : 'u&.(n&|:)'

For rows, you would write

    u"1 onaxes 0

for columns,

    u"1 onaxes 1

You could have

    onaxis =: 2 : 'u"1&.(n&|:)'

but I think that's a special case.

Wait a minute... this means you would have to have an inverse of m&|: .
  What would that be?  I mean, you would have to take the result, which
might have any rank, and undo the transpose...  how?

    2&|: b. _1
(] |:~ 2 C.^:_1 i.@#@$) :.(2&|:)
    3&|: b. _1
(] |:~ 3 C.^:_1 i.@#@$) :.(3&|:)

I can't prove that that's right.  But, knowing Roger, I bet it is.

Henry Rich


On 5/31/2013 8:35 PM, elton wang wrote:
thanks Henry,
to generalize the question, how do I define a conjuction colOrRow such
that for any verb v:
0 colOrRow v is to apply v along row and combine the results row wise,
while 1 colOrRow v is to apply v along column and combine the results
column wise?

I tried colOrRow =. 2 : ' v`(v"1 &.|:)@.m'. but this is not working.




________________________________
  From: Henry Rich <[email protected]>
To: [email protected]
Sent: Friday, May 31, 2013 8:16 PM
Subject: Re: [Jprogramming] zscore in J either column wise or row wise
- basic question on rank


A good testcase for the new dissect tool!


     load '~addons/debug/dissect/dissect.ijs'

     z0 =. (- mean) % stddev
     z0 i. 3 4
|length error: z0
|       z0 i.3 4

what's it doing in there?
     z0 f.
(- (+/ % #)) % %:@(+/@:*:@(-"_1 _ (+/ % #)) % <:@#)

run dissect on that:

     ds '((- (+/ % #)) % %:@(+/@:*:@(-"_1 _ (+/ % #)) % <:@#)) i. 3 4'

the display shows that there is agreement error in (- mean).  Oh yeah,
to work at high rank, you have to put the correct rank on - and %  :

     z0 =. (-"_1 _ mean) %"_1 _ stddev
     z0 i. 3 4
_1 _1 _1 _1
   0  0  0  0
   1  1  1  1
     z0"1 i. 3 4
_1.1619 _0.387298 0.387298 1.1619
_1.1619 _0.387298 0.387298 1.1619
_1.1619 _0.387298 0.387298 1.1619

I don't know if that's correct, but the ranks are right.

Henry Rich

On 5/31/2013 7:57 PM, elton wang wrote:
if I define zscore as  z0 =. (- mean) % stddev, z0 works for rank 1
array.
For a rank 2 array like a=. i. 3 4, if I want to get zscore along
either column or row, I could define
z1 =. [: |: stddev %~ |: - mean


z1 i. 3 3
_1 _1 _1
0  0  0
1  1  1

and

z1"1 i. 3 3
_1 0 1
_1 0 1
_1 0 1

My question is that z1 uses |: twice and looks awkward. If there any
clever way to implement z1 by rank annotation or something?
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