This is documented magic. That said, if you are after any particular part of the docs (for example, for L: or }), we can try pointing you in the right direction?
FYI, -- Raul On Mon, Aug 19, 2013 at 12:32 PM, Pascal Jasmin <[email protected]> wrote: > thanks very much, Don > > I'm not sure if this is undocumented magic for } or for L:0 > > This also works as expected: > > (1 0 ; 4 2 ; 3 3) (0 2}) L:0 (0 1 4; 2 3 4 ; 4 5 4) > > > │1 1 0│4 3 2│3 5 3│ > > > ----- Original Message ----- > From: Don Guinn <[email protected]> > To: Programming forum <[email protected]> > Cc: > Sent: Monday, August 19, 2013 12:19:36 PM > Subject: Re: [Jprogramming] updating a list of boxes > > ( <"0]1 2 3) (0})("0 1) L:0 (0 1 ; 2 3 ; 4 5) > > +---+---+---+ > > |1 1|2 3|3 5| > > +---+---+---+ > > > On Mon, Aug 19, 2013 at 10:10 AM, Pascal Jasmin <[email protected]>wrote: > >> hi again everyone, >> >> I seem stuck in how to do the following: >> >> update a list of boxes y at field 0 with list of replacement values x. >> >> The closest I've gotten is: >> >> ( 1 2 3) (0})("0 1) L:0 (0 1 ; 2 3 ; 4 5) >> >> >> That produces a 3 x 3 array of boxes, with the diagonal the right answer. >> The result I want is: >> >> 1 1 ; 2 3 ; 3 5 >> ---------------------------------------------------------------------- >> For information about J forums see http://www.jsoftware.com/forums.htm >> > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm > > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
