On Sep 17, 2013, at 11:19 AM, "William Tanksley, Jr" <[email protected]> wrote: > > I definitely don't understand what Kip means when he says y=1/x is not > a hyperbola. It is -- it's the second order polynomial xy=0. The > asymptotes happen to be the axes, but that's exactly what rotation > solves. > > -Wm > --------------------------------------------------------------------------------------------------------------- Kip :
What I meant was, there are some hyperbolas you cannot get by rotating the hyperbola y = 1/x , for example you cannot obtain hyperbolas whose asymptotes are not mutually perpendicular. ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
