I always read/interpret "@" or "@:" as "of the"
Took me a while to get this "interpretation" but now I use it all the time
when I write J programs:

rms =: %:@(+/%#)@*:   NB.  square root "of the" mean "of the" squares.


On Mon, Nov 18, 2013 at 6:06 PM, Don Kelly <[email protected]> wrote:

> You sent an answer to my question before I asked it!  Thanks- I suspected
> but didn't know  that this was it.
>
> I think that I will stay with the earlier definition:
>
> rms=:[:%:[:(+/%#)*:
> which, while it does have brackets is somewhat more readable for my present
> state of understanding. Yours is shorter and I expect it would be faster.
> Now all of you have given me enough to digest for now.
> Don
>
>
> On 17/11/2013 7:23 AM, Raul Miller wrote:
>
>> Here's another definition of rms
>>
>>     Rms=: +/@:*: %:@% #
>>     Rms 1 2 1 2
>> 1.58114
>>
>> Explanation:
>>
>> We do not need to square the numbers in the argument to #, we only
>> need to square them in the argument to +/
>>
>> We only need the square root on the result of %
>>
>> Makes sense?
>>
>> Also, here's a partial explanation for the (+/%#)&.:*: definition of RMS
>>
>> &.: means "under" much like &. except that the derived verb has
>> infinite rank - the verb on the left gets the entire array which
>> resulted from the verb on the right, regardless of the rank of the
>> verb on the right. In other words, it is equivalent to (+/ % #) &.
>> (*:"_)  In other words: square the numbers, add them up, divide by
>> their sum, then do the inverse of squaring on the result.
>>
>> Thanks,
>>
>>
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-- 
Piet de Jong
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View my current research at
http://ssrn.com/author=619154
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