I was hoping you'd ask.
1 2 numerize each t
is
1 2 (numerize each) t
and
(numerize each) has rank 0, because each is &.> and that has the rank
from >, i. e. 0 . So (numerize each) applies to atoms, and you have 2
atoms on the left, 3 on the right: length error.
1 2&numerize each t
is
((1 2&numerize) each) t
and ((1 2&numerize) each) again applies to atoms, but this time as a
monad (so no length error possible). It opens each atom of t and then
applies (1 2&numerize) which applies the dyad numerize between 1 2 and
the opened contents of the atom of t.
Henry Rich
On 12/23/2013 1:17 PM, Ricardo Forno wrote:
Thanks.
t =. 1 2 & numerize each t
worked directly without changing "numerize".
However, I stil do not understand completely WHY it worked, ha ha. You
see, I am writing my first important program in J.
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