Joe wonders:
> I also don't really understand why this doesn't work '=:'
> splitstring each ('a=:b';'c=:dz') but I have some hunches
Try
'=:' splitstring each ('a=:b';'c=:d';'e=:f') NB. 2 let args, 3 on right
for a hint.
On Fri, Jan 17, 2014 at 3:22 PM, Joe Bogner <joebog...@gmail.com> wrote:
> On Fri, Jan 17, 2014 at 10:47 AM, R.E. Boss <r.e.b...@planet.nl> wrote:
> >
> > (<'=:') splitstring each ('a=:b';'c=:dz')
>
> > '=:' splitstring L:0 ('a=:b';'c=:dz')
>
> Thanks R.E.
>
> I also had these
>
> '=:'&splitstring each ('a=:b';'c=:dz')
>
> '=:' splitstring "1 > ('a=:b';'c=:dz')
>
> I have no idea what is more idiomatic or if if it matters. I just
> don't want to duct tape together something that others look at and
> wonder what I was thinking.
>
> I also don't really understand why this doesn't work '=:'
> splitstring each ('a=:b';'c=:dz') but I have some hunches
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--
Devon McCormick, CFA
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