Yes, you want 3!7 (the dyadic form of !). 

You'll find that a lot of J primitives are designed so that their monadic
and dyadic valences are thematically related, and frequently their
spelling is mnemonic (or at least suggestive) as well.

-Dan

----- Original Message ---------------

Subject: [Jprogramming] Combinatorial Maths with J
   From: Jon Hough <[email protected]>
   Date: Wed, 26 Feb 2014 15:25:31 +0000
     To: "[email protected]" <[email protected]>

I have a question about doing combinations and permutations with J.
There is an easy to use factorial function (or is that verb) : !
!5120
Is there a combination verb? Or do I make my own?
((!3)*!(7-3))%~!7
Gives 7 choose 3. I think I butchered that. Is there a better way to do
this, without all the brackets?
Now I want to think about more complicated combinatorial objects: Steiner
Systemshttp://en.wikipedia.org/wiki/Steiner_system
Essentially a Steiner System is defined by three numbers a,b,c such that we
have a total of c points and we collect the points into subsets of size b,
such that for any "a" points (where a < b < c) there is exactly one subset
containing all three:example a,b,c=2,3,7 we have the S(2,3,7) steiner
system with points 0~6, the subsets are012   034   056   135   146   236  
245Note, every  pair of points is in exactly one subset.
For a given Steiner system, to calculate the number of subsets (in the
above case 7) there is a simple eqn:
num = (c choose a)/(b choose a)
I would like to write this as a verb (preferrably tacit).I have immediately
run into a problem:this verb would take three arguments. Not sure how to
do that.
I would like some help writing this verb. Thanks in advance. 
Regards,Jon                                       
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