Hmm...
G=:a.i.S=:/:~x
is faster.
But while s-:S, g and G are different.
So I'm drawing a blank here, on how to make the grade.
Thanks,
--
Raul
On Wed, Mar 5, 2014 at 1:52 PM, Roger Hui <rogerhui.can...@gmail.com> wrote:
> Suppose x is a long vector of characters and you need both its sort and its
> grade. Can you do it faster than s=: x{~g=: /:x ?
>
> Posed this way, the answer is of course yes. But how, and why is it
> faster?
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