No, the difference is that the special code for
(i. >./)
actually performs
(i.!.0 >./)
Henry Rich
On 3/14/2014 7:29 PM, Don Guinn wrote:
At first I thought the difference was tacit vs non-tacit. Then I tried
a (i. >./) a
0
The difference must be between monadic and dyadic handling.
On Fri, Mar 14, 2014 at 5:25 PM, Henry Rich <[email protected]> wrote:
Yeah.
Henry Rich
On 3/14/2014 7:23 PM, Don Guinn wrote:
Better?
a=:1(+,-)--:9!:18''
(i. >./) a
1
a i. >./ a
0
On Fri, Mar 14, 2014 at 5:12 PM, Don Guinn <[email protected]> wrote:
oops!
On Fri, Mar 14, 2014 at 5:04 PM, Henry Rich <[email protected]>
wrote:
2nd line needs to be
a i. >./ a
Henry Rich
On 3/14/2014 7:01 PM, Don Guinn wrote:
a=.0 1
(i. >./) a
1
i. >./ a
0
On Fri, Mar 14, 2014 at 1:02 PM, Henry Rich <[email protected]>
wrote:
(i. >./) a
1
a i. >./ a
0
What is a?
Henry Rich
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