The two parts of the definition of Under are equivalent.

  X u&.v y ↔ vi (v x) u (v y)   Definition of Under


I could write a defition of:   . x u&.v y 
'

But could not write a similar tacit verb for:   vi (v x) u (v y)   

So:

g=: 13 :'x(,~&.>)/y'
B g A
-----Original Message-----
From: programming-boun...@forums.jsoftware.com 
[mailto:programming-boun...@forums.jsoftware.com] On Behalf Of Raul Miller
Sent: Friday, April 04, 2014 4:02 AM
To: Programming forum
Subject: Re: [Jprogramming] I want to understand under

What is h supposed to be doing?

Thanks,

-- 
Raul



On Fri, Apr 4, 2014 at 2:25 AM, Linda Alvord <lindaalv...@verizon.net>wrote:

> Here’s the problem.  Hopefully this looks better and fully defines the
> problem.
>
>    f=: 13 :'  (B=:;:''am pm''),~&.>/A=:<"1 ":":"0>:i.y'
>    f 12
> ┌────┬────┬────┬────┬────┬────┬────┬──
> ──┬────┬────┬────┬────┐
> │1 am│2 am│3 am│4 am│5 am│6 am│7 am│8 am│9 am│10am│11am│12am│
> ├────┼────┼────┼────┼────┼────┼────┼──
> ──┼────┼────┼────┼────┤
> │1 pm│2 pm│3 pm│4 pm│5 pm│6 pm│7 pm│8 pm│9 pm│10pm│11pm│12pm│
> └────┴────┴────┴────┴────┴────┴────┴──
> ──┴────┴────┴────┴────┘
>    A
> ┌──┬──┬──┬──┬──┬──┬──┬──┬──┬──┬──┬──┐
> │1 │2 │3 │4 │5 │6 │7 │8 │9 │10│11│12│
> └──┴──┴──┴──┴──┴──┴──┴──┴──┴──┴──┴──┘
>    B
> ┌──┬──┐
> │am│pm│
> └──┴──┘
>    g=: 13 :'x(,~&.>)/y'
>    B g A
> ┌────┬────┬────┬────┬────┬────┬────┬──
> ──┬────┬────┬────┬────┐
> │1 am│2 am│3 am│4 am│5 am│6 am│7 am│8 am│9 am│10am│11am│12am│
> ├────┼────┼────┼────┼────┼────┼────┼──
> ──┼────┼────┼────┼────┤
> │1 pm│2 pm│3 pm│4 pm│5 pm│6 pm│7 pm│8 pm│9 pm│10pm│11pm│12pm│
> └────┴────┴────┴────┴────┴────┴────┴──
> ──┴────┴────┴────┴────┘
>    g
> ,~&.>/
>
>  NB. x u&.v y ↔ vi (v x) u (v y)   Definition of Under
>
>
> I can’t seem to write  a simple definition   h=:       but use the second
> definition of under.
>
> It should have the same result as  B g A  when you enter   B h A
>
> Linda
>
>
>
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>
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