Hi  Jon,

Have you had a chance to watch the J in 10 minutes video that Martin Saurer 
produced a few days ago (link below). About a minute in, Project Euler #1 is 
used as an example to explain a J approach to the problem.

https://www.youtube.com/watch?v=OzaIi8BnHIc&list=PLLcTTp6EQ_egylIerYEjCBbEVhnPzSdXP&index=3

Cheers, bob

On Apr 8, 2014, at 8:39 AM, Lee Fallat <[email protected]> wrote:

> Hey Jon,
> 
> I remember seeing this done by someone before. They went about it like this:
> generate numbers 0 through 1000
> a = i.1000
> create a "mask" list of 0s and 1s where the numbers are divisible by 3 and 5
> <insert J statement that does this...>
> (pseudo code: b = a % 3 OR a % 5)
> multiply the mask list and the number list together
> and
> add all the numbers
> c = +/(a * b)
> 
> Excuse me for my bad J :) I keep learning parts of it but then end up
> not using it for weeks...
> 
> Enjoy,
> 
> Lee
> 
> On Tue, Apr 8, 2014 at 11:30 AM, Jon Hough <[email protected]> wrote:
>> Euler Project  #1 is:If we list all the natural numbers below 10 that are 
>> multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23. 
>> Find the sum of all the multiples of 3 or 5 below 1000.
>> In C/Java I could easily do something like:
>> int total =0;
>> for (int counter = 0; counter < 1000; counter ++ ){if(counter %3 = 0 || 
>> counter %5 = 0){    total += counter;}}
>> return counter;
>> 
>> The main features here being the if statement and the for-loop.
>> Obviously in J things need to be done differently. Here is my first attempt:
>> div3 =. 0&(="0)@:( 3&|) NB. is residue zerodiv5 =. 0&(="0)@:( 5&|)
>> div3or5 =. div3"0 +."0 div5"0
>> dummy =. 1&*"0 NB. You'll see why I need this...
>> result =.  dummy * div3or5
>> NB. final result is:
>> +/result i.1000
>> 
>> I used dummy because I wanted to do something like  multiply the value of y 
>> by "div3or5 y" so only multiples of 3 or 5 would be nonzero.
>> Before attempting this problem I assumed it could be done in only one line 
>> and am pretty unhappy by my long solution. Any help explaining where I have 
>> gone wrong, or why my attempt at a fork is silly would be appreciated.
>> Thanks in advance,
>> Jon
>> 
>> 
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