Thanks Bob

Nice call.  I might start using that, even if only for comparison.
I'll be the first to admit that I haven't been on the friendliest of terms
with the std Vocabulary.  Well, alright... but only sometimes.



On 23 April 2014 18:58, robert therriault <bobtherria...@mac.com> wrote:

> Hey Alex,
>
> You may want to take a look at NuVoc, the jwiki section that I think that
> Ian Clark organized just for the reason that you are describing. :)
>
> http://www.jsoftware.com/jwiki/NuVoc
>
> Cheers, bob
>
>
> On Apr 23, 2014, at 10:52 AM, alexgian <alexg...@blueyonder.co.uk> wrote:
>
> >> The information and more are in the vocabulary page for %.
> >
> > Well, yes, but so tersely and compactly expressed that you have to know
> the
> > long answer before you understand it!  I did look at the Vocab page, but
> > didn't "get it", that's why I posted.
> >
> > It needed Roger's somewhat more expanded explanation for those of us that
> > are somewhat slower on the uptake.  That's why I said the Vocab could
> use a
> > touch up.  It is NOT user friendly, more of an ultra-coded reference.  Of
> > course, you might not see it this way, but I'd bet most newcomers would.
> >
> > And it's not as if there is a longer explanation somewhere else, is
> there?
> > Well, other than this thread, I mean...    :)
> >
> >
> >
> > On 23 April 2014 18:17, Roger Hui <rogerhui.can...@gmail.com> wrote:
> >
> >> The information and more are in the vocabulary page for %.
> >> http://www.jsoftware.com/help/dictionary/d131.htm .
> >>
> >>
> >> On Wed, Apr 23, 2014 at 10:02 AM, alexgian <alexg...@blueyonder.co.uk
> >>> wrote:
> >>
> >>> Great info, thanks Roger.
> >>> If it was up to me, I'd DEFINITELY include that in the Vocabulary, is
> it
> >>> even documented anywhere else?
> >>>
> >>>
> >>> On 23 April 2014 17:33, Roger Hui <rogerhui.can...@gmail.com> wrote:
> >>>
> >>>> %. x for a vector x is the same as ($x)$%.,.x, and the key expression
> >> is
> >>>> %.,.x, the "matrix inverse" of a 1-column matrix.  b=.y%.x on a tall
> >>> matrix
> >>>> x is solving a least-squares problem, the coefficients b that
> minimizes
> >>> the
> >>>> sum of squares of y - x +/ .* b .
> >>>>
> >>>> In addition, for a non-zero vector x, (%.x) +/ .* x is 1, a special
> >> case
> >>> of
> >>>> that (%.x)+/ .* x is an identity matrix, whence one can deduce that
> for
> >>>> vector x, %.x is x%+/x^2.
> >>>>
> >>>>   ] x=: 7 ?.@$ 100
> >>>> 94 56 8 6 85 48 66
> >>>>   %. x
> >>>> 0.00362137 0.00215741 0.000308202 0.000231152 0.00327465 0.00184921
> >>>> 0.00254267
> >>>>   (%.x) +/ .* x
> >>>> 1
> >>>>   x % +/x^2
> >>>> 0.00362137 0.00215741 0.000308202 0.000231152 0.00327465 0.00184921
> >>>> 0.00254267
> >>>>
> >>>>   M=: 7 3 ?.@$ 100
> >>>>   (%.M) +/ .* M
> >>>>           1 5.55112e_17 _2.77556e_17
> >>>> _1.21431e_16           1  1.11022e_16
> >>>> _4.85723e_17 1.94289e_16            1
> >>>>
> >>>>
> >>>>
> >>>> On Wed, Apr 23, 2014 at 9:13 AM, alexgian <alexg...@blueyonder.co.uk>
> >>>> wrote:
> >>>>
> >>>>> Just wondering:
> >>>>> %. 2 3 4
> >>>>>   0.0689655 0.103448 0.137931
> >>>>>
> >>>>> Which is fair enough enough at one level, I suppose, since the dot
> >>>> product
> >>>>> of the two arrays IS 1, but what system/equation is being solved
> >> here?
> >>>>> Obviously, there are infinite solutions.  Why that one?
> >>>>> IOW, which "matrix" is being inverted here?
> >>>>>
> >>>>> Thanks
> >>>>>
> >> ----------------------------------------------------------------------
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> >> http://www.jsoftware.com/forums.htm
> >>>>>
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> >>>>
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> >> ----------------------------------------------------------------------
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> >>
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>
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