>
>
> Would it be possible to write a recursive function that would get your list
> directly as numbers.
>
> Not recursive, but you could do this:


build =: 3 : 0
A=:B,A
B=:A,B
)
((build^:3 '') [ 'A B'=:1 `0)-:(0 1 0 0 1 0 1 0 0 1 0 0 1 0 1 0 0 1 0 1 0)
1
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